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diff --git a/1325/CH6/EX6.3/6_3.sce b/1325/CH6/EX6.3/6_3.sce
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+//to find power absorbed and number of collars required
+clc
+//from equation 6.36 we know, M=(2/3)*u*W*(ri^3-r2^3)/(r1^2-r2^2)
+//given
+u=0.04
+W=16//tons
+w=W*2240//lbs
+r1=8//in
+r2=6//in
+N=120
+P=50//lb/in^2
+M=(2/3)*u*w*(r1^3-r2^3)/(r1^2-r2^2)
+hp=M*2*%pi*N/(12*33000)//horse power absorbed
+//from fig 137,effective bearing surface per pad is calsulate from the dimensions to be 58.5 in^2
+A=58.5//in^2
+n=w/(A*P)
+x=floor(n)
+printf("\n")
+printf("Horsepower absorbed = %.2f\nNumber of collars required = %.f\n",hp,x)