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-rw-r--r--1325/CH3/EX3.3/3_3.PNGbin0 -> 93557 bytes
-rw-r--r--1325/CH3/EX3.3/3_3.sce25
-rw-r--r--1325/CH3/EX3.4/3_4.PNGbin0 -> 100324 bytes
-rw-r--r--1325/CH3/EX3.4/3_4.sce40
-rw-r--r--1325/CH3/EX3.5/3_5.PNGbin0 -> 99106 bytes
-rw-r--r--1325/CH3/EX3.5/3_5.sce28
-rw-r--r--1325/CH3/EX3.6/3_6.PNGbin0 -> 94086 bytes
-rw-r--r--1325/CH3/EX3.6/3_6.sce19
-rw-r--r--1325/CH3/EX3.7/3_7.PNGbin0 -> 96715 bytes
-rw-r--r--1325/CH3/EX3.7/3_7.sce26
-rw-r--r--1325/CH3/EX3.8/3_8.PNGbin0 -> 114807 bytes
-rw-r--r--1325/CH3/EX3.8/3_8.sce34
12 files changed, 172 insertions, 0 deletions
diff --git a/1325/CH3/EX3.3/3_3.PNG b/1325/CH3/EX3.3/3_3.PNG
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diff --git a/1325/CH3/EX3.3/3_3.sce b/1325/CH3/EX3.3/3_3.sce
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+//To find velocities of point p, x and y
+clc
+//Given
+OC=6//in
+CP=24//in
+N=240//rpm
+X=45//degrees
+XP=19//in
+XC=6//in
+YP=32//in
+YC=9//in
+//Scalling off lenghts from fig , we have
+CI=2.77//in
+PI=2.33//in
+XI=2.33//in
+YI=3.48//in
+//Solution
+Vc=((%pi*N)/30)*(OC/12)//changing OP into feets
+printf("\nw=%.2f ft/s\n",Vc)
+//w=Vc/CI=Vp/PI=Vx/XI=Vy/YI
+w=Vc/CI
+Vp=w*PI
+Vx=w*XI
+Vy=w*YI
+printf("velocity of points P, X and Y are %.2f ft/s, %.2f ft/s and %.1f ft/s respectively",Vp,Vx,Vy)
diff --git a/1325/CH3/EX3.4/3_4.PNG b/1325/CH3/EX3.4/3_4.PNG
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diff --git a/1325/CH3/EX3.4/3_4.sce b/1325/CH3/EX3.4/3_4.sce
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+//To find accelerations of point p and x and angular acceleration of rod
+clc
+printf("\n")
+//Given
+OC=9//inches
+CP=36//inches
+XC=12//inches
+X=40//degrees
+CM=6.98//from the scaled figure
+N1=240//rpm
+N2=240//rpm (instantaneous) with angular aceleration (ao) 100 rad/s^2
+ao=100 //rad/s^2
+w=(%pi*N1/30)
+a=w^2*(OC/12)
+printf("Centripetal acceleration = %.f ft/s^2\n",a)
+Wr=w*CM/CP//rad/s^2
+f1=Wr^2*(CP/12)//centripetal component of acceleration of p realtive to C
+//Solution a)
+//given from fig 58(a)
+tp=296
+cp=306
+ox=422
+f2=tp //Tangential component of acceleration of p realtive to C
+f3=cp//acceleration of p realtive to C
+fx=ox//acce;eration of x
+ar=f2/(CP/12)//angular acceleration of rod
+printf("Case a) \nap= %.f ft/s^2,\nax= %.f ft/s^2 and\nar= %.1f rad/s^2 \n",f3,fx,ar)
+//Solution b)
+//given from fig 58(b)
+oc1=474
+oc=480
+pt=238
+pc=246
+xo=452
+f4=pt//Tangential component of acceleration of p realtive to C
+f5=pc//acceleration of p realtive to C
+Ar=f4/(CP/12)//angular acceleration of rod
+f6=ao*(OC/12)//tangential component of acceleration realtive to C
+Fx=xo//acce;eration of x
+printf("Case b) \nap= %.f ft/s^2,\nax= %.f ft/s^2 and\nar= %.1f rad/s^2 \n",f4,Fx,Ar)
diff --git a/1325/CH3/EX3.5/3_5.PNG b/1325/CH3/EX3.5/3_5.PNG
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diff --git a/1325/CH3/EX3.5/3_5.sce b/1325/CH3/EX3.5/3_5.sce
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+//To find angular acceleration of CD and BC
+clc
+//Given
+AB=2.5//inches
+BC=7//inches
+CD=4.5//inches
+DA=8//inches
+N=100//rpm
+X=60//degrees
+w=(%pi*N)/30
+//From triangle ABM we have
+AM=0.14//feet
+BM=0.12//feet
+Vb=w*AB/12//ft/s
+Vc=w*AM//ft/s
+Vcb=w*BM//ft/s
+fb=w^2*(AB/12)//ft/s^2
+bt=Vcb^2/(BC/12)//ft/s^2
+os=Vc^2/(CD/12)//ft/s^2
+//By measurement from acceleration diagram
+sc=19.1//ft/s^2
+tq=14.4//ft/s^2
+Acd=sc/(CD/12)
+Abc=tq/(BC/12)
+printf("\n")
+printf("Vb=%.2f ft/s \nVc=%.2f ft/s\nVcb=%.2f ft/s\nfb=%.2f ft/s^2\nbt=%.2f ft/s^2\nos=%.2f ft/s^2\n",Vb,Vc,Vcb,fb,bt,os)
+printf("Angular acceleration of CD(counter-clockwise)= %.1f rad/s^2 \n",Acd)
+printf("Angular acceleration of BC(counter-clockwise)= %.1f rad/s^2 \n",Abc)
diff --git a/1325/CH3/EX3.6/3_6.PNG b/1325/CH3/EX3.6/3_6.PNG
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diff --git a/1325/CH3/EX3.6/3_6.sce b/1325/CH3/EX3.6/3_6.sce
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+//To find the acceleration of P realative to the fixed point O
+clc
+//Given
+printf("\n")
+OP=2//ft
+f=4//ft/s^2
+w=2 //rad/s (anticlockwise)
+a=5 //rad/s^2 (anticlockwise)
+Vpq=3 //ft/s
+r=OP
+os=w^2*r//component 1
+sq=a*r//component 2
+qt=f//component 3
+tp=2*w*Vpq//component 4
+Aqo=(os^2+sq^2)^1/2//vector addition of component(a,b)
+Apq=(qt^2+tp^2)^1/2//vector addition of component(c,d)
+//Apo=Apq+Aqo (vector addition)
+Apo=((os-qt)^2+(sq+tp)^2)^(1/2)
+printf("Acceleration of P realative to fixed point O is %.1f ft/s^2",Apo)
diff --git a/1325/CH3/EX3.7/3_7.PNG b/1325/CH3/EX3.7/3_7.PNG
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index 000000000..3c2dea696
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diff --git a/1325/CH3/EX3.7/3_7.sce b/1325/CH3/EX3.7/3_7.sce
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index 000000000..31fdca8a3
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+//to find velocity and acceleration of ram R
+clc
+printf("\n")
+//GIVEN
+OC=8//inches
+CP=4//inches
+N=60//inches
+ON=15//inches
+RN=6//inches
+X=120//degrees
+OP=10.6
+OQ=OP
+//from fig 65(a)
+Vq=1.56//ft/s
+Vrn=0.74//ft/s
+//from fig 65(b)
+ftq=3.74//ft/s^2
+ftrn=2.03//ft/s^2
+w1=(%pi*N)/30
+w=Vq/(OQ/12)
+wrn=Vrn/(RN/12)
+a=ftq/(OP/12)//Angular acceleration of ON
+a1=ftrn/(RN/12)//angular acceleration of RN
+printf("W=%.2f rad/s\nWrn=%.2f rad/s\n",w,wrn)
+printf("Angular acceleration of ON= %.2f rad/s^2\nAngular acceleration of RN=%.2f rad/s^2\n",a,a1)
+
diff --git a/1325/CH3/EX3.8/3_8.PNG b/1325/CH3/EX3.8/3_8.PNG
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diff --git a/1325/CH3/EX3.8/3_8.sce b/1325/CH3/EX3.8/3_8.sce
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+//to find the velocity and acceleration of the piston along the cylinder, the angular velocity and angular acceleration of the connecting rod cp and the coriolis component of the acceleration of P
+clc
+//given
+OC=3//inches
+CP=9//inches
+N=1200 //rpm (clockwise)
+X=55 //degrees
+//from the figure 66
+OP=10.35//inches
+PM=10.74//inches
+OM=2.95//inches
+PC=12.84//inches
+PR=PC
+RV=2.49//inches
+UV=1.29//inches
+OU=5.90//inches
+PV=13.05//inches
+OV=6.06//inches
+OQ=OP
+//Solution
+w=(%pi*N)/30//the angular velocity of the cylinder line OP
+Vq=w*(OP/12)//the velocity of Q
+Vp=w*(PM/12)//The velocity of P
+w1=Vp/(CP/12)//The angular velocity of CP
+Vpq=w*(OM/12)//the velocity of sliding of the piston along the cylinder
+fq=w^2*(OQ/12)//the centripetal acceleration of Q
+Acp=w1^2*(PC/12)//The centripetal component of acceleration of P
+Atp=w^2*(RV/12)//The tangential component of acceleration of P
+acp=Atp/(CP/12)// The angular acceleration of the connecting rod CP
+f=w^2*(UV/12)//component c
+d=2*w*Vpq//component d
+Ap=w^2*PV//the resultant acceleration of P
+Apq=w^2*OV//the acceleration of P realative to Q
+printf("\nThe velocity and acceleration of the piston along the cylinder are %.1f ft/s and %.f ft/s^2 respectively\nThe angular velocity and angular acceleration of the connecting rod cp are %.1f rad/s and %.f rad/s^2 respectively\nAnd the coriolis component of the acceleration of P is %.f ft/s^2\n",Vpq,f,w1,acp,d)