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+//to find length of equivalent simple pendulum
+//gravitaional force (g)=32.2 ft/s^2
+clc
+//given
+m1=150 //lb
+l=3//ft
+//number of oscillation per second is given by n
+printf("\n")
+n=(50/92.5)
+printf ("number of oscillation per second = %.2f\n",n)
+//length of simple pendulum is given by L=g/(2*%pi*n)^2
+L=32.2/(2*%pi*n)^2
+printf ("length of simple pendulum = %.2f ft\n",L)
+// distance of cg from point of suspension is given by a
+a=25/12
+k=(a*(L-a))^.5//radius of gyration
+moi=m1*k^2
+printf("The moment of inertia of rod is %.2f lb ft^2",moi)