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diff --git a/1325/CH2/EX2.11/ex2_11.sce b/1325/CH2/EX2.11/ex2_11.sce
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+//to find the maximum acceleration of car on each gear
+//gravitaional force (g)=32.2 ft/s^2
+clc
+printf("\n")
+//let
+//S=displacement of car from rest with uniform acceleration a, the engine torque T assumed to remain ocnstant
+//v=final speed ofcar
+//G=gear ratio
+//r=effective radius
+//n=efficiency of transmission
+//M=mass of the car
+//Ia and Ib=moments of inertia of road whels and engine 
+//formulas => F=29.5nG ; Me= 1648+$.54nG^2 ; a=32.2 F/Me
+//given
+G1=22.5
+G2=12.5
+G3=7.3
+G4=5.4
+n=.82//for 1st ,2nd and 3rd gear
+n4=.9//for 4th gear
+F1=29.5*n*G1
+F2=29.5*n*G2
+F3=29.5*n*G3
+F4=29.5*n4*G4
+//on reduction and putting values we get
+Me1=1648+4.54*n*G1^2
+Me2=1648+4.54*n*G2^2
+Me3=1648+4.54*n*G3^2
+Me4=1648+4.54*n4*G4^2
+a1=32.2*F1/Me1
+a2=32.2*F2/Me2
+a3=32.2*F3/Me3
+a4=32.2*F4/Me4
+printf("Maximum acceleration of car on top gear is %.2f ft/s^2 \n",a4)
+printf("Maximum acceleration of car on third gear is %.2f ft/s^2 \n",a3)
+printf("Maximum acceleration of car on second gear is %.2f ft/s^2 \n",a2)
+printf("Maximum acceleration of car on first gear is %.2f ft/s^2 \n",a1)