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Diffstat (limited to '1325/CH2/EX2.10')
-rw-r--r-- | 1325/CH2/EX2.10/2_10.PNG | bin | 0 -> 96128 bytes | |||
-rw-r--r-- | 1325/CH2/EX2.10/ex2_10.sce | 22 |
2 files changed, 22 insertions, 0 deletions
diff --git a/1325/CH2/EX2.10/2_10.PNG b/1325/CH2/EX2.10/2_10.PNG Binary files differnew file mode 100644 index 000000000..f1e993b2e --- /dev/null +++ b/1325/CH2/EX2.10/2_10.PNG diff --git a/1325/CH2/EX2.10/ex2_10.sce b/1325/CH2/EX2.10/ex2_10.sce new file mode 100644 index 000000000..bfbf4826a --- /dev/null +++ b/1325/CH2/EX2.10/ex2_10.sce @@ -0,0 +1,22 @@ +//to find the acceleration if mass is allowed to fall freely and when efficiency of the gearing were 90%
+//gravitaional force (g)=32.2 ft/s^2
+clc
+//given
+Ia=200//lb ft2
+Ib=15//lb ft2
+G=5//wb==5*wa
+m=150//lb
+r=8//in
+printf("\n")
+//the equivalent mass of the geared system referred to the circumference of the drum is given by
+//Me=(1/r)^2*(Ia+(G^2*Ib))
+Me=(12/r)^2*(Ia+(G^2*Ib))
+M=m+Me
+a=(m/M)*32.2//acceleration
+//if efficiency of gearing is 90% then Me=(1/r^2)*(Ia+(G^2*Ib)/n)
+n=.9
+Me1=(12/r)^2*(Ia+(G^2*Ib)/n)
+M1=Me1+m
+a1=(m/M1)*32.2
+printf("acceleration = %.2f ft/s2\n",a)
+printf("acceleration when gear efficiency is 0.9= %.2f ft/s2\n",a1)
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