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Diffstat (limited to '1325/CH15/EX15.7')
| -rw-r--r-- | 1325/CH15/EX15.7/15_7.PNG | bin | 0 -> 94307 bytes | |||
| -rw-r--r-- | 1325/CH15/EX15.7/15_7.sce | 27 |
2 files changed, 27 insertions, 0 deletions
diff --git a/1325/CH15/EX15.7/15_7.PNG b/1325/CH15/EX15.7/15_7.PNG Binary files differnew file mode 100644 index 000000000..1f95a6e9b --- /dev/null +++ b/1325/CH15/EX15.7/15_7.PNG diff --git a/1325/CH15/EX15.7/15_7.sce b/1325/CH15/EX15.7/15_7.sce new file mode 100644 index 000000000..840abf0f0 --- /dev/null +++ b/1325/CH15/EX15.7/15_7.sce @@ -0,0 +1,27 @@ +//to find the fraction of the applied force transmitted at 1200 rpm and the amplitude of forced vibrations of the machines at resonance
+clc
+//given
+e=1/30
+n=1200//rpm
+w=%pi*n/30
+m=3//lb
+g=32.2//ft/s^2
+stroke=3.5//in
+r=stroke/2
+k=(1+1/e)^(1/2)//nf/n=k
+d=(k/187.7)^2
+W=200//lb ; given
+s=W/d//combined stiffness
+p=1/14.1//As a^2/b=1/198
+T=((1+p^2*k^2/((1-k^2)^2+p^2*k^2)))^(1/2)//actual value of transmissibility
+F=(m/g)*w^2*r/12//maximum unbalanced force transmitted on the machine
+Fmax=F*T//maximum force transmitted to the foundation
+//case b
+E=((1+p^2)/(p^2))^(1/2)
+Nreso=215.5//rpm
+Fub=F*(Nreso/n)^2
+Ftmax=E*Fub
+D=E//dynamic magnifier
+del=Fub/152//static deflection
+A=del*D
+printf("\na) Maximum force transmitted at 1200 rpm = %.f lb\nb) The amplitude of the forced vibrations of the machine at resonance = %.3f in\n Force transmitted = %.f lb\n",Fmax,A,Fub)
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