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+//To find the total forces applied at point A and B
+clc
+//given
+AB=12.5//in
+IB=10.15//in
+IA=10.75//in
+IX=2.92//in
+IY=5.5//in
+w=3//lb
+Fi=5//lb
+Fa1=9//lb
+Fb1=(Fa1*IA-w*IY-Fi*IX)/IB
+//From the polygon of forces
+Fa2=7.66//lb
+Fb2=3.0//lb
+Fa=(Fa1^2+Fa2^2)^(1/2)
+Fb=(Fb1^2+Fb2^2)^(1/2)
+printf("\nThe total force applied to the link AB at the pin A = Fa = %.2f lb\nThe total force applied to the link AB at the pin B = Fb = %.2f lb\n",Fa,Fb)