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+//EMF and copper losses of a Shunt Motor
+
+clc;
+clear;
+
+V=250;
+I=200;
+Ra=0.02; // Armature Resistance
+Rf=50; // Field Resistance
+Pil=950; // Iron and frictional losses
+
+Ish=V/Rf; // Field Current
+Ia=Ish+I; // Armature Current
+
+Pac=(Ia^2)*Ra; // Armature copper loss
+Pfc=(Ish^2)*Rf;// Field copper loss
+
+Pc=Pac+Pfc;
+
+E=V+(Ia*Ra);
+
+Prime=(V*I)+Pil+Pc;// Ouput of prime mover is the input to the generator
+
+eff=(V*I*100)/Prime;
+
+printf('i) The EMF generated = %g V \n',E)
+printf('ii) Total Copper Loss = %g watts \n',Pc)
+printf('iii) Output of the prime mover is %g watts and the efficiency is %g percent \n',Prime,eff)