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+ First,for the nominal resistance values given,
+ the bridge is set at anull with I=0,because
+Va = 0.909091 V
+With I=0 we get
+Vb = 0.909091 V
+When R3 increases by 1 ohm to 1001 ohm, Va becomesVa = 1.666667 V
+which shows that the voltage at b must increase by 0.0008 V to renull the bridge.
+This can be proved by current,from equation and Delta V=0,found from
+I = 0.000016 A \ No newline at end of file