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+clear;
+clc;
+printf("\t\t\tExample Number 1.5\n\n\n");
+// calculating heat flow from tube to the air flowing across it
+// solution
+
+Tw =110 ;//[degree celsius] temperature of the tube
+
+Tf =10 ;//[degree celsius] temperature of the air
+v=5;//[m/s] velocity of air flow
+hm=85;//[W/m^2 degree celcius] mean heat transfer coefficient between tube surface and air for air velocity of 5 m/s across a cylinder
+d=0.01;//[m] outer diameter of the tube
+L=5;
+A= %pi*d*L;//[m^2]total area of the cylinder
+qm=hm*(Tw-Tf);//[W/m^2] heat flux, by Newton's law of cooling
+Q=(qm*A)/1000;//[kW] Heat flow
+printf("The heat flow from the tube to the flowing air is %f kW",Q);
+