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+clear;
+clc;
+//Example 5.8
+Vtn=0.8;
+Kn=0.05;
+//I_D=Kn*(Vgs-Vtn)^2
+//Vds=Vgs=5-I_D*Rs
+//combining these two equations we obtain 0.5(Vgs)^2+0.2Vgs-4.68
+Vgs=poly(0,'Vgs')
+p=poly([-4.68 0.2 0.5],'Vgs','c')
+printf('\npossible solutions ::%.3f V\n',roots(p))
+//assuming transistor is conducting ,Vgs must be greater than threshold voltage
+Vgs=2.87;
+I_D=Kn*(Vgs-Vtn)^2;
+printf('\ndrain current=%.3f mA\n',I_D)