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diff --git a/1223/CH2/EX2.3/Ex2_3.sce b/1223/CH2/EX2.3/Ex2_3.sce
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+++ b/1223/CH2/EX2.3/Ex2_3.sce
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+clear;
+clc;
+//Example 2.3
+V_O=12;//(V)peak output voltage
+I_L=0.12;//(A)current delivered to the load
+R=V_O/I_L;
+printf('\neffective load resistance=%.2f Ohm\n',R)
+V_Y=0.7;//(V)diode cut in voltage
+v_S=V_O+2*V_Y;
+printf('\npeak value of v_S=%.2f V\n',v_S)
+v_Srms=v_S/sqrt(2);
+printf('\nrms voltage=%.2f V\n',v_Srms)
+//let x=N1/N2
+Vin=120;//(V)input line voltage
+x=Vin/v_Srms;
+printf('\nturns ratio=%.2f \n',x)
+VM=12;//(V)
+Vr=5/100*VM;
+printf('\nripple voltage=%.2f V\n',Vr)
+f=60;//(Hz) input frequency
+C=VM/(2*R*Vr*f);
+printf('\nfilter capacitance=%f F\n',C)
+i_Dmax=(VM/R)*(1+2*%pi*sqrt(VM/(2*Vr)));
+printf('\npeak diode current=%.2f A\n',i_Dmax)
+R=0.1;//Kohm
+i_Davg=(1/(2*%pi))*sqrt(2*Vr/VM)*((VM/R)*(1+%pi*sqrt(VM/(2*Vr))));
+printf('\naverage diode current=%f mA\n',i_Davg)
+PIV=v_S-V_Y;
+printf('\npeak inverse voltage=%.2f V\n',PIV)