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+clear;
+clc;
+//Example 13.5
+bp=50;
+bn=200;
+Va=50;
+R9=50;
+R8=0.100;
+Rl=2;
+Vt=0.026;
+Ri2=4070;
+Ic20=0.138;
+r20=bp*Vt/Ic20;
+printf('\nr20=%.2f KOhm\n',r20)
+R20=r20+(1+bp)*Rl;
+printf('\nR20=%.2f KOhm\n',R20)
+Ic13A=0.18;
+R19=Va/Ic13A;
+printf('\nR19=%.2f KOhm\n',R19)
+r22=bp*Vt/Ic13A;
+printf('\nr22=%.2f KOhm\n',r22)
+Ri3=r22+(1+bp)*R19*R20/(R19+R20);
+Ri3=Ri3*0.001;//MOhm
+printf('\ninput resistance to the output stage=%.2f MOhm\n',Ri3)
+Ic13B=0.54;
+R=Va/Ic13B;
+printf('\neffective resistance of the active load=%.2f KOhm\n',R)
+Ic17=Ic13B;
+R17=Va/Ic17;
+printf('\noutput resistance Ro17 =%.2fKOhm\n',R17)
+Ri3=Ri3*1000;//KOhm
+r17=9.63;
+x=R17*Ri3/(Ri3+R17);
+y=x*R/(R+x);
+A=-bn*R9*(1+bn)*y/(Ri2*(R9+r17+(1+bn)*R8));
+printf('\nsmall signal voltage gain=%.2f\n',A)