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+clear;
+clc;
+//Example 13.4
+b=200;
+Va=50
+Vt=0.026;
+R2=1;
+Ic6=0.0095;
+Ic4=Ic6;
+Ic16=0.0158;
+Ic17=0.54;
+r17=b*Vt/Ic17;
+printf('\ninput resistance to gain stage=%.2f KOhm\n',r17)
+R9=50;
+R8=0.100;
+x=r17+(1+b)*R8;
+Re=x*R9/(x+R9);
+printf('\nRe=%.3f KOhm\n',Re)
+r16=b*Vt/Ic16;
+printf('\nr16=%.2f KOhm\n',r16)
+Ri2=r16+(1+b)*Re;
+Ri2=Ri2*0.001;//MOhm
+printf('\nRi2=%.2f KOhm\n',Ri2)
+r6=b*Vt/Ic6;
+printf('\nresistance of the active load=%.2f KOhm\n',r6)
+gm=Ic6/Vt;
+printf('\ntransconductance =%.3fmA/V\n',gm)
+ro6=Va/Ic6;
+ro6=ro6*0.001;//MOhm
+printf('\nro6=%.2f MOhm\n',ro6)
+R=ro6*(1+gm*R2*r6/(R2+r6));
+printf('\neffective resistance of active load=%.2f MOhm\n',R)
+ro4=Va/Ic4;
+ro4=ro4*0.001;//Mohm
+printf('\nResistance ro4=%.2f KOhm\n',ro4)
+Icq=9.5;
+x=Ri2*R/(R+Ri2);
+y=ro4*x/(ro4+x);
+Ad=-y*Icq/Vt;
+printf('\nsmall signal differential voltage gain=%.2f\n',Ad)