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+clc;
+
+h=500;//N, horizontal force
+W=1.5;//kN, weight of block
+W=W*1000;//N. conversion to N
+us=0.25;// Coeffiecient of static friction
+uk=0.20;//Co=efficient of kinetic friction
+
+//Applying sumFx =0 , we get
+F=-4/5*h+3/5*W;//N, Force along plane
+
+//Applying sumFy=0, we get
+N=4/5*W+3/5*h;//N, Normal force to the plane
+
+printf("Force F required to maintain the equillibrium is thus %.0f N, up and to right\n",F);
+
+// Maximum friction force
+Fm=us*N;//N,Maximum friction force
+printf("Maximum friction force is %.2f N is less than that of required to maintain equillibrium that is %.2f N \n So, equillibrium will nat maintain and block wil move down\n",Fm,F);
+// Actual value of friction force
+Fk=uk*N;//N, Actual value of friction force
+printf("Actual value of friction force is %.2f N directed up and to the right\n",Fk);