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-rw-r--r--1205/CH6/EX6.5/S_6_5.sce38
1 files changed, 38 insertions, 0 deletions
diff --git a/1205/CH6/EX6.5/S_6_5.sce b/1205/CH6/EX6.5/S_6_5.sce
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+clc;
+P=18;//kN, Force applied at D
+AF=3.6;//m, Length AF
+EF=2;//m, Length EF
+ED=2;//m, Length ED
+DC=2;//m, Length DC
+//Entire frame
+//Applying sum(M_F)=0
+Ay=-P*(EF+ED)/AF;//kN, Y component of reaction at A
+
+//Applying sum(Fx)=0
+Ax=-P;//kN, X component of reaction at A
+//Applying sum(Fy)=0
+F=-Ay;//kN, reaction at B
+
+
+printf("Components of force exerted at A is Ax=%.0f kN and Ay=%.0f kN \n",Ax,Ay);
+printf("Force exerted at F is F=%.0f kN \n",F);
+//Free body member BE
+//Applying sum(Fx)=0
+//B=E, and as it is 2 force member
+By=0;
+Ey=0;
+
+//Member ABC
+//Applying sum(Fy)=0
+Cy=-Ay;//kN, Y component of force exerted at C
+//Applying sum(M_C)=0
+B=(Ay*AF-Ax*(DC+ED+EF))/(ED+DC);//kN, Force in link DE
+printf("Force exerted at B is B=%.0f kN \n",B);
+//Applying sum(Fx)=0
+Cx=-Ax-B;//kN, X component of force exerted at C
+
+printf("Components of force exerted at C is Cx=%.0f kN and Cy=%.0f kN \n",Cx,Cy);
+
+printf("Negative signs shows forces are in negative direction\n")
+
+