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-rw-r--r--1205/CH5/EX5.9/S_5_9.sce28
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+clc;
+n=2; // no of triangle
+A=[4.5,13.5];//kN, loads
+x=[2,4];//mm, distances of centroid from point A
+
+sumA=0;
+sumxA=0;
+for(i=1:n)
+ sumA=sumA+A(i);
+ sumxA=sumxA+x(i)*A(i);
+
+end
+
+
+//Location of centroid
+X=sumxA/sumA;// X co-ordinate
+W=sumA;//kN, Concentrated load
+printf("The equivalent concentrated mass is W= %.0f kN and its line of action is located at a distance X= %.1f m to the right of A \n",W,X);
+
+// Reactions
+// Applying sum(F_x)=0
+Bx=0;//N
+//Applying sum(M_A)=0
+By=W*X/6;//kN, Reaction at B in Y direction
+//Applying sum(M_B)=0
+A=W*(6-X)/6;//kN, Reaction at B in Y direction
+
+printf("The rection at A=%.1f kN, At Bx=%.1f kN and By=%.1f kN \n",A,Bx,By);