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+clc;
+//Determination of B
+//At equillibrium +sum(M_A)=0
+//B*1.5m-(9.81kN)(2 m)-(23.5 kN)(6 m)=0, B assumed to be in +ve X direction
+B=(9.81*2+23.5*6)/1.5//kN
+printf("B=%.2f kN \n +ve sign shows reaction is directed as assumed ",B);
+//Determination of Ax
+//Sum Fx=0
+//Ax+B=0
+Ax=-B;//kN
+printf("Ax=%.2f kN\n",Ax);
+//Determination of Ay
+//Sum Fy=0
+//Ay-9.81 kN-23.5kN=0
+Ay=9.81+23.5;//kN
+printf("Ay=%.2f kN\n",Ay);
+A=[Ax,Ay];//kN Adding component
+A=norm(A);//Magnitude of force A
+theta=atan(Ay/Ax);//radians
+theta=theta*180/%pi;//degrees, conversion into degrees
+printf("Reaction at A is A=%.2f kN making angle %.2f degrees with + ve x axis ",A,theta);