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-rw-r--r--1205/CH2/EX2.6/S_2_6.sce22
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diff --git a/1205/CH2/EX2.6/S_2_6.sce b/1205/CH2/EX2.6/S_2_6.sce
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+clc;
+alpha=atan(7/4);//rad
+beta=atan(1.5/4);//rad
+T_AB=200;//N tension in cable AB
+T_AE=-300;//N, tension in cable AE
+// R= T_AB+T_AC+T_AE+F_D=0 ...Equillibrium Condition...........1
+
+
+T_ABx=-T_AB*sin(alpha);// Xcomponent of T_AB
+T_ABy=T_AB*cos(alpha);//Y component of T_AB
+
+// T_ACx=T_AC*sin(beta); Xcomponent of T_AC
+// T_ACy=T_AC*cos(beta); Y component of T_AC
+
+// Sum Fx =0 gives -T_AB*sin(alpha) N + T_AC*sin(beta) +F_D=0..........2
+//Sum Fy=0 gives T_AB*cos(alpha) N +T_AC*cos(beta) +T_AE =0................3
+
+T_AC=(-T_AB*cos(alpha)-T_AE)/cos(beta);//N, From 3
+
+F_D=T_AB*sin(alpha)-T_AC*sin(beta);//N, From 2
+
+printf("Value of drag force is F_D=%.2f N and tension in cable AC is T_AC= %.2f N",F_D,T_AC);