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+clc;
+
+mA=200;//kg, mass of block A
+mB=300;//kg, mass of block B
+x=2;//m, displacement of block A
+uk=0.25;// Coefficient of kinetic friction
+
+g=9.81;//m/s^2, Acceleration due to gravity
+WA=mA*g;//N, Weight of block A
+WB=mB*g;//N, Weight of block B
+FA=uk*WA;//N, frictional force
+//By principle of work and energyon block A
+//0+Fc*x-FA*x=1/2*mA*v^2
+//By principle of work and energyon block B
+//0+WB*x-Fc*x=1/2mB*v^2
+
+//Adding above equations we get
+
+//WB*x-FA*x=1/2*(mA+mB)*v^2, therefore
+v=sqrt((WB*x-FA*x)*2/(mA+mB));//m/s, velocity of block A
+
+printf("Therfore velocity of block A after it has been moved 2 mm is v= %0.2f m/s \n",v);