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+clc
+
+u_m = 50; // m/s or 180 km/h
+v=1.5*10^(-5); // m^2/s
+l=100; // m
+rho=1.2; // kg/m^3
+b=8.3; // m
+
+delta = 0.37*(v/u_m)^(1/5)*l^(4/5);
+
+disp("(a) the boundary layer thickness at the rear of the train =")
+disp(delta)
+disp("m")
+
+Re_l = u_m*l/v;
+C_F=0.074*(Re_l)^(-1/5);
+F=0.037*rho*u_m^2*l*Re_l^(-1/5);
+
+D_F = F*b;
+
+disp("(b) the frictional drag acting on the train, D_F =")
+disp(D_F)
+disp("N")
+
+P=D_F*u_m;
+disp("(c) the power required to overcome the frictional drag =")
+disp(P/1000)
+disp("kW")