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diff --git a/1092/CH4/EX4.13/Example4_13.sce b/1092/CH4/EX4.13/Example4_13.sce new file mode 100755 index 000000000..f7df7860b --- /dev/null +++ b/1092/CH4/EX4.13/Example4_13.sce @@ -0,0 +1,43 @@ +// Electric Machinery and Transformers
+// Irving L kosow
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 4: DC Dynamo Torque Relations-DC Motors
+// Example 4-13
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+V_a = 120 ; // Rated terminal voltage of dc shunt notor in volt
+R_a = 0.2 ; // Armature resistance in ohm
+BD = 2 ; // Brush drop in volt
+I_a = 75 ; // Full load armature current in A
+I_a_new = 1.5 * I_a ; // armature current in A at 150% rated load
+
+E_c_a = 0 ; // Back EMF at starting
+E_c_b = ( 25 / 100 ) * V_a ; // Back EMF in volt is 25% of Va @ 150% rated load
+E_c_c = ( 50 / 100 ) * V_a ; // Back EMF in volt is 50% of Va @ 150% rated load
+
+// Calculations
+R_s_a = ( V_a - E_c_a - BD ) / I_a_new - R_a ; // Ra tapping value at starting
+// in ohm
+R_s_b = ( V_a - E_c_b - BD ) / I_a_new - R_a ; // Ra tapping value @ 25% of Va
+// in ohm
+R_s_c = ( V_a - E_c_c - BD ) / I_a_new - R_a ; // Ra tapping value @ 50% of Va
+// in ohm
+E_c_d = V_a - ( I_a * R_a + BD ) ; // Back EMF @ full-load without starting resistance
+
+// Display the results
+disp(" Example 4-13 Solution : ");
+printf(" \n a: At starting, Ec is zero ");
+printf(" \n Rs = %.2f ohm \n ", R_s_a );
+
+printf(" \n b: When back EMF in volt is 25 percent of Va @ 150 percent rated load ");
+printf(" \n Rs = %.3f ohm \n ", R_s_b );
+
+printf(" \n c: When back EMF in volt is 50 percent of Va @ 150 percent rated load ");
+printf(" \n Rs = %.3f ohm \n ", R_s_c );
+
+printf(" \n d: Back EMF at full-load without starting resistance ");
+printf(" \n Ec = %d V ", E_c_d );
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