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Diffstat (limited to '1092/CH14/EX14.9/Example14_9.sce')
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1 files changed, 42 insertions, 0 deletions
diff --git a/1092/CH14/EX14.9/Example14_9.sce b/1092/CH14/EX14.9/Example14_9.sce new file mode 100755 index 000000000..46385c495 --- /dev/null +++ b/1092/CH14/EX14.9/Example14_9.sce @@ -0,0 +1,42 @@ +// Electric Machinery and Transformers
+// Irving L kosow
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 14: TRANSFORMERS
+// Example 14-9
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+kVA = 1 ; // kVA rating of the transformer
+V_1 = 220 ; // Primary voltage in volt
+V_2 = 110 ; // Secondary voltage in volt
+f_o = 400 ; // Frequency in Hz(original frequency)
+f_f = 60 ; // Frequency in Hz for which the transformer is to be used
+
+// Calculations
+alpha = V_1 / V_2 ; // Transformation ratio
+// case a
+E_h = V_1 * (f_f / f_o); // Maximum rms voltage in volt applied to HV side
+E_1 = E_h ;
+E_l = E_1 / alpha ; // Maximum rms voltage in volt applied to HV side
+
+// case b
+V_h = V_1 ; // High voltage in volt
+I_h = kVA * 1000 / V_h ;
+Vh = E_h ;
+kVA_new = Vh * I_h ;
+
+// Display the results
+disp("Example 14-9 Solution : ");
+
+printf(" \n a: To maintain the same permissible flux density in Eqs.(14-15)");
+printf(" \n and (14-16),both voltages of the high and low sides must change ");
+printf(" \n in the same proportion as the frequency : ");
+printf(" \n E_h = %d V \n and,\n E_l = %.1f V\n",E_h , E_l );
+
+printf(" \n b: The original current rating of the transformer is unchanged since");
+printf(" \n the conductors still have the same current carrying capacity.");
+printf(" \n Thus,\n I_h = %.3f A\n and the new kVA rating is",I_h );
+printf(" \n V_h*I_h = V_1*I_1 = %d VA = %.2f kVA",kVA_new , kVA_new/1000);
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