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+// Electric Machinery and Transformers
+// Irving L kosow 
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 14: TRANSFORMERS
+// Example 14-6
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+P = 100 ; // Power rating of the single channel power amplifier in W
+Z_L1 = 8 ; // Amplifier output in ohm using a tapped impedance-matching transformer
+Z_L2 = 4 ; // Amplifier output in ohm using a tapped impedance-matching transformer
+P_servo = 10 ; // Power rating of the servo motor in W
+Z_servo = 0.7 ; // Impedance of the servo motor in ohm
+
+// Calculations
+root_Z_AB = sqrt(8) - sqrt(4);
+Z_AB = (root_Z_AB)^2;
+
+// Display the resulta
+disp("Example 14-6 Solution : ");
+
+printf(" \n Z_p = %dΩ*(N_p/N_1)^2 = %dΩ*(N_p/N_2)^2\n",Z_L2,Z_L1);
+printf(" \n     = Z_AB * (N_p/(N_2 - N_1)^2 ) \n");
+printf(" \n Dividing each of the three numerators by N_p^2 and taking the ");
+printf(" \n square root of each term, we have\n");
+
+printf(" \n √(Z_AB)/(N_2 - N_1) = √(4)/N_1 = √(8)/N_2 \n");
+printf(" \n √(Z_AB)/(N_2 - N_1) = √(4)/N_1 - √(8)/N_2 \n");
+printf(" \n yielding, √(Z_AB) = √(8) - √(4) = %f \n",root_Z_AB);
+printf(" \n which Z_AB = (%f)^2 = %.2f Ω \n",root_Z_AB,Z_AB);
+
+