1 files changed, 43 insertions, 0 deletions
diff --git a/1092/CH14/EX14.32/Example14_32.sce b/1092/CH14/EX14.32/Example14_32.sce
new file mode 100755
index 000000000..4a4641079
--- /dev/null
+++ b/1092/CH14/EX14.32/Example14_32.sce
@@ -0,0 +1,43 @@
+// Electric Machinery and Transformers
+// Irving L kosow 
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 14: TRANSFORMERS
+// Example 14-32
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+S_1 = 10 ; // VA rating of small transformer
+V = 115 ; //  voltage rating of transformer in volt
+V_2_1 = 6.3 ; // voltage rating of one part of secondary winding in volt
+V_2_2 = 5.0 ; // voltage rating of other part of secondary winding in volt
+Z_2_1 = 0.2 ; // impedance of one part of secondary winding in ohm
+Z_2_2 = 0.15 ; // impedance of other part of secondary winding in ohm
+
+
+// Calculations
+// case a
+V_2 = V_2_1 + V_2_2 ; // voltage across secondary winding in volt
+I_2 = S_1 / V_2 ; // Rated secondary current in A when the LV secondaries are
+// connected in series-aiding
+
+// case b
+I_c = (V_2_1 - V_2_2) / (Z_2_1 + Z_2_2); // Circulating current when LV windings are paralled
+percent_overload = (I_c / I_2)*100 ; // percent overload produced
+
+// Display the results
+disp("Example 14-32 Solution : ");
+
+printf(" \n a: Both coils must be series-connected and used to account for the ");
+printf(" \n    full VA rating of the transformer. Hence,the rated current in 5 V ");
+printf(" \n    and 6.3 V winding is : \n");
+printf(" \n    I_2 = %.3f A \n\n", I_2);
+
+printf(" \n b: When the windings are paralleled, the net circulating current is ");
+printf(" \n    the net voltage applied across the total internal impedance of ");
+printf(" \n    the windings,or :\n");
+printf(" \n    I_c = %.2f A \n ",I_c);
+
+printf(" \n    The percent overload is = %f percent ≃ %.f percent ",percent_overload,percent_overload);