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+// Electric Machinery and Transformers
+// Irving L kosow 
+// Prentice Hall of India
+// 2nd editiom
+
+// Chapter 14: TRANSFORMERS
+// Example 14-30
+
+clear; clc; close; // Clear the work space and console.
+
+// Given data
+// subscripts a,b,c for the current, voltages indicates respective cases a ,b ,c.
+// from fig.14-27a
+V_pa = 1000 ; // Phase voltage in volt
+I_1a = 1 ; // line current in primary in A
+V_2a = 100 ; // voltage across secondary in V
+Ic_a = 10 ; // current in lower half of auto-transformer in A
+
+// from fig.14-26b
+V_s = 100 ; // voltage in secondary wdg in V
+I_2b = 10 ; // current in secondary in A
+V_1b = 1000 ; // voltage across primary in V
+Ic_b = 1 ; // current in lower half of auto-transformer in A
+
+// Calculations
+// case a
+S_T1 = (V_pa*I_1a + V_2a*I_1a)/1000 ; // Total kVA transfer in step-down mode
+
+// case b
+S_T2 = (V_s*I_2b + V_1b*I_2b)/1000 ; // Total kVA transfer in step-up mode
+
+// case c
+S_x_former_c = V_pa*I_1a/1000 ; // kVA rating of th autotransformer  in Fig.14-27a
+
+// case d
+V_1 = V_pa ;
+S_x_former_d = V_1*Ic_b/1000  ; // kVA rating of th autotransformer  in Fig.14-26b
+
+
+// Display the results
+disp("Example 14-30 Solution : ");
+
+printf(" \n a: Total kVA transfer in step-down mode :\n    S_T = %.1f kVA transferred \n",S_T1);
+
+printf(" \n b: Total kVA transfer in step-up mode :\n    S_T = %.1f kVA transferred \n",S_T2);
+
+printf(" \n c: kVA rating of th autotransformer in Fig.14-27a:\n    S_x-former = %d kVA \n ",S_x_former_c);
+
+printf(" \n d: kVA rating of th autotransformer in Fig.14-26b:\n    S_x-former = %d kVA \n ",S_x_former_d);
+
+printf(" \n e: Both transformers have the same kVA rating of 1 kVA since the same ");
+printf(" \n    autotransformer is used in both parts.Both transformers transform ");
+printf(" \n    a total of 1 KVA. But the step-down transformer in part(a) conducts ");
+printf(" \n    only 0.1 kVA while the step-up transformer in the part(b) conducts 10");
+printf(" \n    kVA from the primary to the secondary.");