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+clc;
+clear;
+//Example 6.2
+m_dot=10000 //Weak liquor entering in [kg/h]
+fr_in=0.04 //Fraciton of caustic soda IN i.e 4%
+fr_out=0.25 //Fraciton of caustic soda OUT i.e 25%
+//Let mdash_dot be the kg/h of thick liquor leaving
+mdash_dot=fr_in*m_dot/fr_out //[kg/h]
+
+//Overall material balance
+//kg/h of feed=kg/h of water evaporated +kg/h of thick liquor
+//we=water evaporated in kg/h
+//Therefore
+we=m_dot-mdash_dot //[kg/h]
+printf("\n Capacity of evaporator is %d kg/h",we);