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+clc;
+clear;
+//Example 6.16
+bpr=40.6; //[K]
+Cpf=1.88; //[kJ/kg.K]
+Hf=214; //[kJ/kg]
+H1=505; //[kJ/kg]
+mf_dot=4536; //[kg/h] of feed solution
+ic=0.2; //Initial conc
+fc=0.5; //Final concentration
+m1dot_dash=(ic/fc)*mf_dot //Thisck liquor flow arte[kg/h]
+mv_dot=mf_dot-m1dot_dash //[kg/H]
+Ts=388.5; //Saturation temperature of steam in [K]
+bp=362.5 //b.P of solution in [K]
+lambda_s=2214; //[kJ/kg]
+P=21.7; //Vapor space in [kPa]
+Hv=2590.3; //[kJ/kg]
+
+//Enthalpy balance over evaporator
+ms_dot=(m1dot_dash*H1+mv_dot*Hv-mf_dot*Hf)/lambda_s //[kg/h
+printf("\nSteam consumption is %f kg/h\n",ms_dot);
+dT=Ts-bp //[K]
+U=1560 //[W/sq m.K]
+Q=ms_dot*lambda_s //[kJ/h]
+Q=Q*1000/3600 //[W]
+A=Q/(U*dT) //[sq m]
+printf("\nHeat transfer area is %f sq m\n",A);
+
+//Calculations considering enthalpy of superheated vapour
+
+Hv=Hv+Cpf*bpr //[kJ/kg]
+ms_dot=(m1dot_dash*H1+mv_dot*Hv-mf_dot*Hf)/lambda_s //[kg/h]
+printf("\n Now,Steam consumption is %f kg/h\n",ms_dot);
+eco=mv_dot/ms_dot //Steam economy
+printf("\nEconomy of evaporator %f\n",eco);
+Q=ms_dot*lambda_s //[kJ/h]
+Q=Q*1000/3600 //[w]
+A2=Q/(U*dT) //Area
+printf("\nNow,Area is %f\n",A);
+perc=(A2-A)*100/A //%error in the heat transfer area
+printf("\n If enthalpy of water vapour Hv were based on the saturated vapour at the pressure\nthe error introduced is only %f percent\n",perc);