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diff --git a/1040/CH7/EX7.6.a/Chapter7_Ex6_a.sce b/1040/CH7/EX7.6.a/Chapter7_Ex6_a.sce new file mode 100644 index 000000000..9fce8ca2c --- /dev/null +++ b/1040/CH7/EX7.6.a/Chapter7_Ex6_a.sce @@ -0,0 +1,44 @@ +//Harriot P,2003,Chemical Reactor Design (I-Edition) Marcel Dekker,Inc., USA,pp 436.
+//Chapter-7 Ex7.6.a Pg No.300
+//Title:Fraction of O2 used
+//======================================================================================================================
+clear
+clc
+//INPUT
+Vol_reactor=200;//Volume of reactor (m3)
+D=4;//Diameter of reactor (m)
+depth=12;//Depth of reactor (m)
+u_g=3;//Superficial velocity (cm/sec)
+T_C=30;//Temperature (°C)
+T_K=273+T_C;//Temperature (K)
+f_O2=0.21;//Fraction of O2 in air
+myu_soln=1.5*(10^(-3));//Viscosity of solution (Pa sec)
+R=0.08206;//Gas constant (m3 atm/ K kmol)
+r_O2_peak=45*(10^(-3));//Flow rate of O2 at peak demand
+
+//CALCULATION
+S=%pi*(D^2)/4;//Cross section area (m2)
+V=S*depth;//Volume of solution(m3)
+F_air=(S*u_g*(10^(-2))*3600)/(R*(10^(-3))*T_K);
+F_O2=f_O2*F_air;//Feed rate of O2 (mol/hr)
+F_O2_used=r_O2_peak*V*(10^(3));//O2 used for aerobic fermentation (mol/hr)
+F_O2_left=F_O2-F_O2_used;//O2 left after aerobic fermentation(mol/hr)
+f_O2_exitgas=F_O2_left/F_air;//Fraction of O2 in exit gas
+Percent_O2_exitgas=(f_O2_exitgas)*(100);
+Frac_O2_used=((f_O2-f_O2_exitgas)/f_O2);
+
+//OUTPUT
+//Console Output
+mprintf('\n\tAt the peak demand, fraction of the oxygen supplied = %.3f ',Frac_O2_used);
+//File Output
+fid= mopen('.\Chapter7_Ex6_a_Output.txt','w');
+mfprintf(fid,'\n\tAt the peak demand, fraction of the oxygen supplied = %.3f ',Frac_O2_used);
+mclose('all');
+//===================================================END OF PROGRAM======================================================
+//Disclaimer: The numerically calculated value of oxygen fraction supplied is 0.592 not 0.591 as mentioned in the textbook
+
+
+
+
+
+
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