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+//Example 3.14
+clear;
+clc;
+
+//Given 
+delHsubLi = 161;//heat of sublimation of Li in kJ 
+delHsubNa = 109;//heat of sublimation of Na in kJ
+delHd = 122;//heat of dissociation of chlorine in kJ
+delHaff = -350;//electron affinity of Cl in kJ
+delHipLi = 520;// ionization potential of Li in kJ
+delHipNa = 496;//ioization potential of Na in kJ
+delHfLiCl = -410;//heat of formation of LiCl in kJ
+delHfNaCl = -411;//heat of formation of NaCl in kJ
+delHLisol= -35.1;//heat of solution of LiCl in kJ
+delHNasol= 4.3;//heat of solution of NaCl in kJ
+
+//To determine the (a) enthalpy change (b) heat of hydration
+delHcLiCl = delHsubLi+delHd+delHipLi+delHaff-delHfLiCl;//born haber cycle
+mprintf('(a) heat of formation of LiCl crystal = %f kJ',delHcLiCl);
+delHcNaCl = delHsubNa+delHd+delHipNa+delHaff-delHfNaCl;//born haber cycle
+mprintf('\n heat of formation of NaCl crystal = %f kJ',delHcNaCl);
+delHLiCl = delHLisol-delHcLiCl;//heat of hydration of LiCl in kJ
+delHNaCl = delHNasol-delHcNaCl;//heat of hydration of NaCl in kJ
+mprintf('\n \n (b) heat of hydration of LiCl = %f kJ',delHLiCl);
+mprintf('\n heat of hydration of NaCl = %f kJ',delHNaCl);
+//end
+\ No newline at end of file