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+//Example 2.18
+clear;
+clc;
+
+//Given
+R=8.314;// gas constant in J K^-1 mol^-1
+q=1675;//heat absorbed in J mol^-1
+Cp=2.5*R; //specific heat capacity at constant pressure of the gas in J K^-1 mol^-1
+n=1;//moles of the gas
+T1=273; //initial temperature in K
+delH=2078.5;//enthalpy change in J mol^-1
+P1=1;//initial pressure in atm
+
+// To determine P2,w,delE and T2
+Cv=Cp-R;//specific heat capacity at constant volume of the gas in J K^-1 mol^-1
+T2=T1+(delH/Cp);//final temperature in K
+delE=n*Cv*(T2-T1);//internal energy change in J mol^-1
+w=q-delE;//work done in J mol^-1
+P2=(P1*T2)/(T1*2);//final pressure in atm
+mprintf('delE = %f J mol^-1',delE);
+mprintf('\n work done = %f J mol^-1',w);
+mprintf('\n Final temperature = %f K',T2);
+mprintf('\n Final pressure = %f atm',P2);
+//end
+\ No newline at end of file