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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clc;
+clear all;
+disp("Heat loss rate")
+La=0.12;//m
+Lb=0.24;//m
+kA=1.7;// W/(m*C)
+kB=5.8;// W/(m*C)
+Rcont=0.0035;// C/W
+t1= 725;// degree C
+t4=110;// degree C
+RthA=La/kA;// C/W
+RthB=Lb/kB;// C/W
+Rth= RthA+Rcont+RthB;// C/W
+q= (t1-t4)/Rth;// W/m^2
+disp("W/m^2",q,"rate of heat loss per unit area of the wall is =")
+// q= (t1-t2)/RthA= (t3-t4)/RthB
+t2=t1-q*RthA;// degree C
+t3=q*RthB+t4;// degree C
+disp ("degree C",t2-t3,"the temperature drop is = ")