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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /944/CH5/EX5.39/example5_39_TACC.sce | |
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-rwxr-xr-x | 944/CH5/EX5.39/example5_39_TACC.sce | 20 |
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diff --git a/944/CH5/EX5.39/example5_39_TACC.sce b/944/CH5/EX5.39/example5_39_TACC.sce new file mode 100755 index 000000000..3b234bdfb --- /dev/null +++ b/944/CH5/EX5.39/example5_39_TACC.sce @@ -0,0 +1,20 @@ +//example 5.39
+
+clear;
+clc;
+
+disp("0.5N2(g)+1.5H2(g)<=>NH3(g)");
+//Given:
+T=298;//Temperature[K]
+Kp=900;//Equilibrium constant for above reaction
+P1=0.32;//partial pressure of N2(g)[bar]
+P2=0.73;//partial pressure of H2(g)[bar]
+P3=0.98;//partial pressure of NH3(g)[bar]
+R=8.314;//Universal gas constant[J/K/mol]
+
+//To find the reaction Gibb's energy
+G=-R*T*log(Kp);
+x=(P1^0.5)*(P2^1.5);
+p=P3/x;
+Gr=(G+R*T*log(p))*0.001;
+printf("The reaction Gibbs free energy is %f KJ/mol ",Gr);
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