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+//example 5.22

+

+clear;

+clc;

+

+disp("C6H12O6(s)+6O2(g)-->6CO2(g)+6H2O(l)");

+//Given:

+mass=25;//mass of glucose for combustion under standard condition[gm]

+T=298;//temperature[K]

+Gf1=-910;//Standard Gibbs free energy of formation for C6H12O6[KJ/mol]

+Gf2=-394.4;//Standard Gibbs free energy of formation for CO2(g)[KJ/mol]

+Gf3=-237.13;//Standard Gibbs free energy of formation for H2O(l)[KJ/mol]

+mol.wt=180;//molecular weight of glucose[gm/mol]

+

+//To find the maximum energy that can be extracted as non-expansion work is equal to the change in free energy of the system

+G=6*Gf2+6*Gf3-Gf1

+n=mass/mol.wt;//no. of moles

+Gactual=G*n;//Gibbs free energy for the combustion of 0.139mol of glucose 

+printf("The energy that can be extracted as non-expansion work is %f KJ",-Gactual);