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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /926/CH3/EX3.8/Chapter3_Example8.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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| -rw-r--r-- | 926/CH3/EX3.8/Chapter3_Example8.sce | 30 |
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diff --git a/926/CH3/EX3.8/Chapter3_Example8.sce b/926/CH3/EX3.8/Chapter3_Example8.sce new file mode 100644 index 000000000..110a96fb7 --- /dev/null +++ b/926/CH3/EX3.8/Chapter3_Example8.sce @@ -0,0 +1,30 @@ +//Hougen O.A., Watson K.M., Ragatz R.A., 2004. Chemical process principles Part-1: Material and Energy Balances(II Edition). CBS Publishers & Distributors, New Delhi, pp 504
+
+//Chapter-3, Illustration 8, Page 61
+//Title: Calculation of density of air
+//=============================================================================
+clear
+clc
+
+//INPUT
+N = 1; //Total no moles of air in g mole
+n = [.21,.79]; //No of moles of O2 and N2 respectively in g mole
+MW = [32,28]; //Moleculaw weight of O2 and N2 respectively in g/g mole
+T = 70; //Given temperature in dergee F
+P1 = 741; //Given pressure in mm Hg
+T2 = 492; //Temperature at standard conditions in degree R
+P2 = 760; //Pressure at standard conditions in mm Hg
+V2 = 22.41; //Volume at standard conditions in liters
+
+//CAlCULATIONS
+w1 = n(1)*MW(1); //Weight of O2 in grams
+w2 = n(2)*MW(2); //Weight of N2 in grams
+W = w1+w2; //Total weight of air in grams
+T1 = T+460; //Given temperature in dergree R
+V1 = V2*(P2/P1)*(T1/T2); //Volume of air at given conditions in liters
+rho = W/V1; //Dendity of air at given conditions in grams per liter
+
+//OUTPUT
+mprintf('\n The density of air at %3.0f mm Hg and %2.0f degree F is %4.3f grams per liter', P1,T,rho);
+
+//==========================END OF PROGRAM=====================================
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