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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc;
+warning("off");
+printf("\n\n example12.3 - pg569");
+U=3; //[m/sec]
+x1=1; //[m]
+x2=2; //[m]
+p=1/(1.001*10^-3); //[kg/m^3];
+mu=1*10^-3; //[kg/m*sec]
+Nre1=(x1*U*p)/(mu);
+Nre2=(x2*p*U)/(mu);
+tauw=(1/2)*(p*(U^2))*((2*log10(Nre1)-0.65)^(-2.3));
+B=1700;
+Cd=(0.455*(log10(Nre2))^-2.58)-(B/(Nre2));
+Lb=2.0;
+F=(1/2)*(p*(U^2))*(Lb)*(Cd);
+printf("\n\n the drag on the plate is \n F = %f kg*m/sec^2 = %f N",F,F);
+
+