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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+
+// Illustration 7.9
+// Page: 460
+
+printf('Illustration 7.9 - Page: 460\n\n');
+
+// solution
+//*****Data*****//
+// From example 7.8
+Di = 0.288; // [m]
+sigma = 0.025; // [N/m]
+ohm = 152*1.2/60; // [rps]
+ds = 868; // [kg/cubic m]
+phiD = 0.385;
+
+// Therefore from equation 7.49
+We = Di^3*ohm^2*ds/sigma; // [Weber number]
+
+// From equation 7.50
+dvs = Di*0.052*(We)^-0.6*exp(4*phiD); // [m]
+disp(dvs);
+// Substituting in equation 7.48
+a = 6*phiD/dvs; // [square m/cubic m]
+printf("The Sauter mean drop diameter and the interfacial area is %e m and %f square m/cubic m respectively.\n\n",dvs,a); \ No newline at end of file