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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+
+// Illustration 2.2
+// Page: 95
+
+printf('Illustration 2.2 - Page: 95\n\n');
+
+// solution
+
+//*****Data*****//
+// a-ammonia b-air
+T = 300; // [K]
+P = 1; // [atm]
+y_a1 = 0.8; // [ammonia mole fraction in the bulk of the gas phase]
+y_a2 = 0.732; // [ammonia gas-phase mole fraction on interface]
+N_a = 4.3*10^-4; // [ammonia flux, kmole/square m.s]
+//*****//
+
+// Using equation 2.2
+F_g = N_a/log((1-y_a2)/(1-y_a1)); // [kmole/square m.s]
+printf("The mass-transfer coefficient in the gas phase at that point where flux is 4.3*10^-4 is %e kmole/square m.s\n\n",F_g); \ No newline at end of file