initial commit / add all books

6 files changed, 58 insertions, 0 deletions

diff --git a/887/CH7/EX7.1/7_1.sce b/887/CH7/EX7.1/7_1.sce
new file mode 100755
index 000000000..17e0c0842
--- /dev/null
+++ b/887/CH7/EX7.1/7_1.sce
@@ -0,0 +1,5 @@
+clc

+//ex7.1

+N=343;      //decimal integer

+N2=dec2bin(N);      //binary equivalent of N

+disp(N2,'Binary equivalent of 343 is')

diff --git a/887/CH7/EX7.2/7_2.sce b/887/CH7/EX7.2/7_2.sce
new file mode 100755
index 000000000..e2bf5bfe9
--- /dev/null
+++ b/887/CH7/EX7.2/7_2.sce
@@ -0,0 +1,19 @@
+clc

+//ex7.2

+N=0.392;      //decimal

+DP=N;      //decimal part(no integer part)

+i=1;

+x=1;

+//Each decimal digit is stored in D(x)

+while (x<=9)

+DP=DP*2;

+D(x)= floor (DP);

+x=x+1;

+DP= modulo (DP ,1);

+end

+DP=0;

+for j=1: length (D)

+//bits of decimal part are multiplied with their position values and adding them

+    DP=DP+(10^(-1*j)*D(j));

+end

+disp(DP,'Binary form of 0.392 is')

diff --git a/887/CH7/EX7.3/7_3.sce b/887/CH7/EX7.3/7_3.sce
new file mode 100755
index 000000000..b56e34b69
--- /dev/null
+++ b/887/CH7/EX7.3/7_3.sce
@@ -0,0 +1,9 @@
+clc

+//ex7.3

+N=343.392;

+//convert the integer and decimal parts into binary form separately

+B_1='101010111';      //for 343 from ex7.1

+B_2='0.011001';      //for 0.392 from ex7.2

+//combining these two

+B='101010111.011001';      //for N, given number

+disp(B,'binary form of 343.392')

diff --git a/887/CH7/EX7.4/7_4.sce b/887/CH7/EX7.4/7_4.sce
new file mode 100755
index 000000000..42bad2413
--- /dev/null
+++ b/887/CH7/EX7.4/7_4.sce
@@ -0,0 +1,6 @@
+//ex7.4

+N_1=1000.111;

+N_2=1100.011;

+//Adding these two according to the rules of binary addition in fig7.6, we get

+disp("The result of addition of given two binary numbers is")

+disp("10101.010")

diff --git a/887/CH7/EX7.5/7_5.sce b/887/CH7/EX7.5/7_5.sce
new file mode 100755
index 000000000..612d8d5b1
--- /dev/null
+++ b/887/CH7/EX7.5/7_5.sce
@@ -0,0 +1,10 @@
+clc

+//ex7.5

+//Given 317.2 (octal)and F3A.2 (hexadecimal)

+//From table 7.1 in text, corresponding octal forms of 3,1,7 and 2 are 011,001,111 and 010

+disp('The binary representation of 317.2(octal) is ')

+disp('011001111.010')

+disp('')

+//From table 7.1 in text, corresponding hexadecimal forms of F,3,A and 2 are 1111,0011,1010 and 0010

+disp('The binary representation of F3A.2(hexadecimal) is ')

+disp('111100111010.0010')

diff --git a/887/CH7/EX7.6/7_6.sce b/887/CH7/EX7.6/7_6.sce
new file mode 100755
index 000000000..a8b246f72
--- /dev/null
+++ b/887/CH7/EX7.6/7_6.sce
@@ -0,0 +1,9 @@
+clc

+//ex7.6

+//Given 11110110.1(binary)

+//Working outward from the binary point, we form three-bit groups ==> 11110110.1=011 110 110. 100(we have appended leading and trailing zeros so that each group contains 3 bits)

+//And the corresponding numbers for 011,110,110 and 100 in octal system are 3,6,6 and 4

+disp('The octal representation of 11110110.1(binary) is 366.4')

+//Now we form four-bit groups appending leading and trailing zeros as needed ==> 11110110.1=1111 0110. 1000

+//The corresponding numbers for 1111,0110 and 1000 in hexadecimal system are F,6 and 8

+disp('The hexadecimal representation of 11110110.1(binary) is F6.8')