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authorpriyanka2015-06-24 15:03:17 +0530
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+clc
+//ex2.20
+V_s_1=20; //voltage source
+R_1=5;
+R_2=10;
+i_s_1=1; //current source
+//Method 1: To transform current source and R_2 into a voltage source in series with R_2
+V_s_2=i_s_1*R_2; //source transformation
+i_1=(V_s_1-V_s_2)/(R_1+R_2); //clockwise KVL
+i_2=i_1+i_s_1; //KCL at top node of original circuit
+printf(" All the values in the textbook are approximated hence the values in this code differ from those of Textbook")
+disp('By current source to voltage source transformation:')
+disp(i_1,'current i1 in amperes')
+disp(i_2,'current i2 in amperes')
+//Method 2: To transform voltage source and R_1 into a current source in parallel with R_1
+i_s_2=V_s_1/R_1; //source transformation
+i_t=i_s_2+i_s_1; //total current
+i_2=R_1*i_t/(R_1+R_2) //current-division principle
+i_1=i_2-i_s_1; //KCL at top node of original circuit
+disp('By voltage source to current source transformation:')
+disp(i_1,'current i1 in amperes')
+disp(i_2,'current i2 in amperes')
+disp('In any method we get the same answers.')
+