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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+//ex2.17
+V_s=20; //source voltage
+i_s=2; //source current
+R_1=5;
+R_2=20;
+//after zeroing the sources which includes replacing voltage source with short circuit and current source with open circuit, we get R_t
+R_eq=1/((1/R_1)+(1/R_2)); //R_1 and R_2 are in parallel combination
+R_t=R_eq; //Thevenin resistance
+//short-circuit analysis to find i_sc
+i_2=0; //voltage across R_2 is 0
+i_1=V_s/R_1;
+i_sc=i_1+2-i_2; //short-circuit current(KCL at junction of R_2 and I_s)
+V_t=R_t*i_sc; //thevenin voltage
+disp(i_sc,'short-circuit current in amperes')
+disp(R_t,'thevenin resistance in ohms')
+disp(V_t,'thevenin voltage in volts')
+//thevenin equivalent can be made of V_t and R_t.