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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clc
+clear
+printf("example 6.8 page number 229\n\n")
+
+//to find the mean driving force and mass transfer area
+
+Gs=700/22.4 //in kmol of dry air/hr
+Ls=1500/18 //in kmol of dry air/hr
+y1=0.05
+Y1=y1/(1-y1);
+Y2=0.02*Y1;
+X2=0
+X1=(Gs/Ls)*(Y1-Y2);
+m=Gs*(Y1-Y2);
+
+//driving force
+delta_Y1=Y1-1.68*X1;
+delta_Y2=Y2-1.68*X2;
+delta_Y=(delta_Y1-delta_Y2)/(log (delta_Y1/delta_Y2));
+printf("driving force = %f kmol acetone/kmol dry air",delta_Y)
+
+//mass transfer area
+K_G=0.4 //in kmol acetone/kmol dry air
+A=m/(K_G*delta_Y);
+printf("\n\narea = %f sq m",A)