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+//clear//

+//Caption:Program to find the output power and attenuation coefficient

+//Example11.4

+//page349

+clear;

+clc;

+close;

+z = 20; //distance in meters

+Pz_P0_dB = -2; //fraction of power drop in dB

+Pz_P0 = 10^(Pz_P0_dB/10);

+disp(Pz_P0,'Fraction of input power reaches output P(z)/P(0)=')

+P0_mid_dB = -1; //fraction of power drop at midpoint in dB

+P0_mid = 10^(P0_mid_dB/10);

+disp(P0_mid,'Fraction of the input power reaches the midpoint P(10)/P(0)=')

+alpha = -Pz_P0_dB/(8.69*z);

+disp(alpha,'attenuation in Np/m alpha=')

+//Result

+//Fraction of input power reaches output P(z)/P(0)=   

+//     0.6309573  

+//Fraction of the input power reaches the midpoint P(10)/P(0)=   

+//    0.7943282  

+//attenuation in Np/m alpha=   

+//    0.0115075