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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
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tree | ab291cffc65280e58ac82470ba63fbcca7805165 /839/CH18/EX18.3/Example_18_3.sce | |
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diff --git a/839/CH18/EX18.3/Example_18_3.sce b/839/CH18/EX18.3/Example_18_3.sce new file mode 100755 index 000000000..cd43921a9 --- /dev/null +++ b/839/CH18/EX18.3/Example_18_3.sce @@ -0,0 +1,47 @@ +//clear//
+clear;
+clc;
+
+//Example 18.3
+//Given
+mdot = 30000; //[kg/h]
+wF_b = 40;
+wD = 97;
+wB = 2;
+R = 3.5;
+lambda_b = 7360; //[cal/g mol]
+lambda_t = 7960; //[cal/g mol]
+alpha = 2.5;
+TB = 95; //[C]
+TF = 20; //[C]
+P = 1; //[atm]
+Mb = 78;
+Mt = 92;
+Cp = 0.44; //[cal/g-C]
+//Solution
+xF = (wF_b/Mb)/(wF_b/Mb+((100-wF_b)/Mt));
+xD = (wD/Mb)/(wD/Mb+((100-wD)/Mt));
+xB = (wB/Mb)/(wB/Mb+((100-wB)/Mt));
+//The average molecular weight of the feed is
+Mavg = 100/(wF_b/Mb+(100-wF_b)/Mt);
+//the average heat of vaporization
+lambda_avg = xF*lambda_b+(1-xF)*lambda_t; //[cal/g mol]
+//Feed rate
+F = mdot/Mavg; //[kg mol/h]
+//Using Eq.(18.5), by overall benzene balance
+D = F*(xF-xB)/(xD-xB); //[kg mol/h]
+B = F-D; //[kg mol/h]
+//Using Table 18.3, in all three cases respectively
+xprime = [0.44,0.521,0.3];
+yprime = [0.658,0.730,0.513];
+
+//(a)
+//Using Eq.(18.43)
+RDm = (xD-yprime)./(yprime-xprime)
+disp('respectively',RDm(3),RDm(2),RDm(1),'Minimum Reflux Ratio for three cases is')
+
+//(b)
+//For minimum umber of plates the, the reflux ratio is infinite, the operating lines
+//coincides with the diagonal, and there are no differences between the three cases.
+//The plot is given by Fig 18.22. A reboiler and eight plates are needed.
+
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