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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Caption:(a)How much KVA should be supplied by synchronous motor (b)Power factor of synchronous motor
+//Exa:15.7
+clc;
+clear;
+close;
+Pm=40//Power absorb by motor(in Kw)
+Pl=300//Load connected in parallel with motor(in KW)
+pfm=0.85//Power factor of motor
+pfl=0.9//Power factor on load
+Pt=Pl+Pm
+Pr=Pt*tand(acosd(pfl))
+Pri=Pl*tand(acosd(pfm))
+Ps=Pri-Pr
+pf=cosd(atand(Ps/Pm))
+disp(Ps,'(a)Power supplied by synchronous motor(in KVA)=')
+disp(pf,'(b)Power factor of synchronous machine=') \ No newline at end of file