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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /83/CH5/EX5.5/example_5_5.sce | |
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initial commit / add all books
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-rwxr-xr-x | 83/CH5/EX5.5/example_5_5.sce | 29 |
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diff --git a/83/CH5/EX5.5/example_5_5.sce b/83/CH5/EX5.5/example_5_5.sce new file mode 100755 index 000000000..8c627311f --- /dev/null +++ b/83/CH5/EX5.5/example_5_5.sce @@ -0,0 +1,29 @@ +//Chapter 5 +//Example 5.5 +//page 147 +//to find maximum permissible length and and frequency +clc;clear; +R=0.125*400; +X=0.4*400; +Y=2.8*(10^-6)*400*%i; +Z=R+X*%i; + +//(i) At no-load +A=1+(Y*Z/2); +C=Y*(1+Y*Z/6); +VR_line=220000/abs(A); +Is=abs(C)*VR_line/sqrt(3); +printf('\n\n |VR|line = %d kV',VR_line/1000); +printf('\n |Is| = %d A',Is); + +//(ii) to find maximum permissible length +//By solving the equations shown in the book,we get +l=sqrt((1-0.936)/(0.56*10^(-6))); +printf('\n\n Maximum permissible length of the line = %d km',l); + +//(iii) to find maximum permissible frequency for the case(i) +//By solving the equations shown in the book,we get +f=sqrt(((1-0.88)*50*50)/(0.5*1.12*10^-3*160)); +printf('\n\n Maximum permissible frequency = %0.1f Hz\n\n',f); + + |