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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 5
+//Example 5.5
+//page 147
+//to find maximum permissible length and and frequency
+clc;clear;
+R=0.125*400;
+X=0.4*400;
+Y=2.8*(10^-6)*400*%i;
+Z=R+X*%i;
+
+//(i) At no-load
+A=1+(Y*Z/2);
+C=Y*(1+Y*Z/6);
+VR_line=220000/abs(A);
+Is=abs(C)*VR_line/sqrt(3);
+printf('\n\n |VR|line = %d kV',VR_line/1000);
+printf('\n |Is| = %d A',Is);
+
+//(ii) to find maximum permissible length
+//By solving the equations shown in the book,we get
+l=sqrt((1-0.936)/(0.56*10^(-6)));
+printf('\n\n Maximum permissible length of the line = %d km',l);
+
+//(iii) to find maximum permissible frequency for the case(i)
+//By solving the equations shown in the book,we get
+f=sqrt(((1-0.88)*50*50)/(0.5*1.12*10^-3*160));
+printf('\n\n Maximum permissible frequency = %0.1f Hz\n\n',f);
+
+