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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /83/CH12/EX12.6/example_12_6.sce | |
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-rwxr-xr-x | 83/CH12/EX12.6/example_12_6.sce | 23 |
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diff --git a/83/CH12/EX12.6/example_12_6.sce b/83/CH12/EX12.6/example_12_6.sce new file mode 100755 index 000000000..1507d88a4 --- /dev/null +++ b/83/CH12/EX12.6/example_12_6.sce @@ -0,0 +1,23 @@ +//Chapter 12 +//Example 12.6 +//page 457 +//To find steady state power limit +clear;clc; + +V=1.0; //infinite bus volatge +Vt=1.2; //terminal volatge +Xd=0.5*%i; //synchronous generator reactance +X=%i; //series reactance +//by solving the expressions given in the textbook +theta=acosd(0.5/1.8); +printf('\n\ntheta=%0.3f deg',theta); +Vt=Vt*(cosd(theta)+%i*sind(theta)); +printf('\nVt=%0.3f+j%0.3f pu',real(Vt),imag(Vt)); +I=(Vt-V)/X; +printf('\nI=%0.3f+j%0.3f pu',real(I),imag(I)); +E=Vt+Xd*I; +printf('\nE=%0.3f @ %d deg pu',abs(E),atand(imag(E)/real(E))); +Pmax=(abs(E)*abs(V))/abs(X+Xd); +printf('\n\nSteady state power limit is given by:\tPmax=%0.3f pu',Pmax); +E=1.2;Pmax=(abs(E)*abs(V))/abs(X+Xd); +printf('\n\nIf the generator emf is held fixed at a value 1.2pu,steady state power limit would be :\t Pmax=%0.2f pu\n\n',Pmax);
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