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authorpriyanka2015-06-24 15:03:17 +0530
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-rwxr-xr-x83/CH12/EX12.4/example_12_4.sce20
-rwxr-xr-x83/CH12/EX12.4/result_example_12_4.txt7
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+//Chapter 12
+//Example 12.4
+//page 453
+//To calculate acceleration and rotor angle
+clear;clc;
+
+delta0=33.9; //initial rotor angle
+H=4; //inertia constant
+f=50; //frequency
+Pm=1; //mechanical power input
+t=0.05; //time interval
+angular_acceleration=(Pm-0.694*sind(delta0))*180*f/H;
+delta_change=0.5*angular_acceleration*t^2;
+delta_new=delta0+delta_change;
+new_angular_acceleration=(Pm-0.694*sind(delta_new))*180*f/H;
+
+printf('\n\nInitial rotor angular acceleration = %d elect deg/s^2',angular_acceleration);
+printf('\nDelta_change=%0.1f deg',delta_change);
+printf('\nNew delta =delta1=%0.1f deg',delta_new);
+printf('\nAngular acceleration at the end of 0.05s =%d elect deg/s^2\n\n',new_angular_acceleration);
diff --git a/83/CH12/EX12.4/result_example_12_4.txt b/83/CH12/EX12.4/result_example_12_4.txt
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+
+
+Initial rotor angular acceleration = 1379 elect deg/s^2
+Delta_change=1.7 deg
+New delta =delta1=35.6 deg
+Angular acceleration at the end of 0.05s =1340 elect deg/s^2
+