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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 11
+//Example 11.1
+//page 406
+//To draw sequence networks of generator and to compare LG fault current will be greater than three-phase fault current when neutral is solidly grounded
+clear;clc;
+
+disp("Sequence networks of synchronous generator grounded through neutral impedance has been drawn using XCOS ");
+
+disp("Since the derivation can not be done here, let us do this problem by taking a suitable values for the sequence reactances of the generator");
+
+disp("X1=j0.18, X2=j0.15, X0=j0.10 pu and Ea=1");
+
+disp("From the figs 11.13 and 11.14 in the textbook,we can find Ilg and I3L");
+
+Ea=1;X1=0.18*%i;X2=0.15*%i;X0=0.10*%i;
+
+IaLG=3*Ea/(2*X1+X0)
+Ia3L=3*Ea/(3*X1)
+
+disp("Same values of sequence impedance have been used in XCOS simulation also to varify the result");