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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /83/CH10/EX10.4/example_10_4.sce | |
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diff --git a/83/CH10/EX10.4/example_10_4.sce b/83/CH10/EX10.4/example_10_4.sce new file mode 100755 index 000000000..33f6f06e2 --- /dev/null +++ b/83/CH10/EX10.4/example_10_4.sce @@ -0,0 +1,33 @@ +//Chapter 10 +//Example 10.4 +//page no 392 +//To draw the zero sequence networks of the system given in example 10.2 +clear;clc; + +//selecting generator rating as base in generator circuit + +mvab=25; +kvGb=11; //base voltage for generator +kvTLb=kvGb*(121/10.8); //base voltage for TL +kvMb=kvTLb*(10.8/121); //base voltage for motors + +//Calculation of zero sequence reactance + +xT0=0.0805; //zero sequence reactance of transformer +xG0=0.06; //zero sequence reactance of generator + +//zero sequence reactanc eof motors +xM1_0=0.06*(mvab/15)*(10/kvMb)^2; +xM2_0=0.06*(mvab/7.5)*(10/kvMb)^2; + +x_clr_0=3*2.5*(mvab/kvGb^2); // Reactance of current limiting reactors to be icluded in the zero sequence network +x_TL_0=300*(mvab/kvTLb^2); //Zero sequence reactance of TL + +printf('\n\nTransformer zero sequence reactance = %0.4f pu',xT0); +printf('\nGenerator zero sequence reactances = %0.2f pu',xG0); +printf('\nZero sequence reactance of motor 1 = %0.3f pu',xM1_0); +printf('\nZero sequence reactance of motor 2 = %0.3f pu',xM2_0); +printf('\nReactance of current limiting reactors = %0.3f pu',x_clr_0); +printf('\nZero sequence reactance of transmission line = %0.3f pu\n\n',x_TL_0); + +disp('Zero sequence diagram has been drawn using XCOS,simulation has not been done as it is not being asked in the problem');
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